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Is it possible to constrain a login/password for to the very specific domain name (i.e. including sub-domain names) it is linked to?

Alexis Wilke
Alexis Wilke
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I work with a company that has two distinct websites and thus I use two distinct passwords.

One website has a domain name similar to https://www.example.com/ and the other is like https://foo.example.com/

I want to save the login/password for the first one (www) but not the second one (foo). However, when I go to the login form of the second one, Firefox offers me to fill in the form with the info from the first site (www), which is wrong. Would there be a way to hide that form from the second site? I find that confusing.

I work with a company that has two distinct websites and thus I use two distinct passwords. One website has a domain name similar to https://www.example.com/ and the other is like https://foo.example.com/ I want to save the login/password for the first one (www) but not the second one (foo). However, when I go to the login form of the second one, Firefox offers me to fill in the form with the info from the first site (www), which is wrong. Would there be a way to hide that form from the second site? I find that confusing.

Chosen solution

This feature is mentioned in release notes of version 71: Firefox now suggests saved logins from other subdomains of a site.

To turn it off, enter about:config in the url bar and set signon.includeOtherSubdomainsInLookup = false.

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All Replies (2)

TyDraniu
TyDraniu
  • Top 10 Contributor
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Chosen Solution

This feature is mentioned in release notes of version 71: Firefox now suggests saved logins from other subdomains of a site.

To turn it off, enter about:config in the url bar and set signon.includeOtherSubdomainsInLookup = false.

Alexis Wilke
Alexis Wilke Question owner
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Excellent! That worked. Personally I prefer it this way, really.

In a way, it's sad that we have to go to about:config to tweak all those settings. On the other hand, I know that's way too many options to keep them in preferences. Anyway, thank you for solving this one.